-16x^2+68x+60=0

Solution for -16x^2+68x+60=0 equation:

-16x^2+68x+60=0

a = -16; b = 68; c = +60;
Δ = b2-4ac
Δ = 682-4·(-16)·60
Δ = 8464
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{8464}=92$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(68)-92}{2*-16}=\frac{-160}{-32}
=+5
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(68)+92}{2*-16}=\frac{24}{-32}
=-3/4
$